# Line slope calculator 9x+y=55

**Straight line given by points A[5; 10] and B[6; 1]**

## Calculation:

**Slope-intercept form of line:**y = -9x+55

**Canonical form of the line equation:**9x+y-55 = 0

**Parametric form of the line equation:**

x = t+5

y = -9t+10 ; t ∈ R

**Slope:**m = -9

**Slope angle of line: φ =**-83°39'35″ = -1.4601 rad

**X intercept:**x

_{0}= 6.1111

**Y intercept:**y

_{0}= q = 55

**Distance line from the origin:**d

_{0}= 6.0737

**The length of the segment AB: |AB| =**9.0554

**Vector: AB =**(1; -9)

**Normal vector: n =**(9; 1)

**Midpoint of the segment AB: M =**[5.5; 5.5]

**Perpendicular Bisector equation:**x-9y+44 = 0

**Vector OA = (5; 10) ; |OA| = 11.1803**

**Vector OB = (6; 1) ; |OB| = 6.0828**

**Scalar product OA .OB = 40**

**Angle ∠ AOB = 53°58'21″ = 0.942 rad**